Let p be -24 and q be 4.
p/3q = -24/3(4) = -24/12 = -2
Answer: -2
T=time
d=st
r=train speed
p=plane speed
<span>160=rt
</span><span>720=pt
speed of plan is 20kmph less than 5 times speed of train
p=5r-20
we notice that 160 times 4.5=720
times first equaton by 4.5
720=4.5rt
720=pt
set equal
4.5rt=pt
divide both sides by t
4.5r=p
sub </span><span>p=5r-20 for p
4.5r=5r-20
minus 4.5r from both sides
0=0.5r-20
add 20 to both sides
20=0.5r
times 2 both sides
40=r
sub back</span><span>
p=5r-20
p=5(40)-20
p=200-20
p=180
plane is 180kmph
train is 40kmph
</span>
Answer:
1) 16
2a) 100 -a -2b
2bi) (100 -a -2b)/4
2bii) 11
Step-by-step explanation:
1. Put the numbers where the corresponding variables are and do the arithmetic.
(2(1) +3(-2))^2 = (2 -6)^2 = (-4)^2 = 16
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2. The pieces cut from the wire have the lengths a, b, b. The sum of those lengths is a+b+b = a+2b.
2a. The remaining length is what is left when the total of cut pieces is subtracted from the original amount:
100 -(a+2b) = 100 -a -2b
2bi. The perimeter of the square is the amount in part (2a). A square has 4 sides of the same length, so each side has a length that is 1/4 of the perimeter. The side length is ...
(100 -a -2b)/4 . . . . length of one side of the square
2bii. Fill in the given values for "a" and "b" and do the arithmetic.
(100 -24 -2(16))/4 = (76 -32)/4 = 44/4 = 11 . . . one side of the square
