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Anni [7]
3 years ago
8

Is my answer on the photo correct? ​

Mathematics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

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Can somebody help me find the perimeter of this figure?
lbvjy [14]

Answer: P = 64in,

Step-by-step explanation:  P = 17 + 13 + 25 + 9

3 0
3 years ago
0.59 O 2/3<br><br> A. =<br> B. &gt;<br> C. &lt;<br> D. none of the above
egoroff_w [7]
0.59 and 2/3

0.59
0.66

0.59 < 2/3

2/3 is greater than 0.59.

Answer :
6 0
3 years ago
Which of these number lines represents the difference -3-2​
Yuki888 [10]

Answer:

Number line D

Step-by-step explanation:

That line goes from 0 to -3 and subtracts 2, as the equation shows.

6 0
3 years ago
Find the equation of ellipse passing throgh (1,4) and (-3,2)​
irinina [24]

Answer:

\displaystyle  \frac{  {3x}^{2} }{ 35 }  +  \frac{{2y}^{2} }{  35  }   = 1

Step-by-step explanation:

we want to figure out the ellipse equation which passes through <u>(</u><u>1</u><u>,</u><u>4</u><u>)</u><u> </u>and <u>(</u><u>-</u><u>3</u><u>,</u><u>2</u><u>)</u>

the standard form of ellipse equation is given by:

\displaystyle  \frac{(x - h {)}^{2} }{ {a}^{2} }  +  \frac{(y - k {)}^{2} }{ {b}^{2} }  = 1

where:

  • (h,k) is the centre
  • a is the horizontal redius
  • b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

\displaystyle  \frac{  {x}^{2} }{ {a}^{2} }  +  \frac{{y}^{2} }{ {b}^{2} }  = 1

substituting the value of x and y from the point (1,4),we'd acquire:

\displaystyle  \frac{ 1}{ {a}^{2} }  +  \frac{16}{ {b}^{2} }  = 1

similarly using the point (-3,2), we'd obtain:

\displaystyle  \frac{ 9}{ {a}^{2} }  +  \frac{4 }{ {b}^{2} }  = 1

let 1/a² and 1/b² be q and p respectively and transform the equation:

\displaystyle  \begin{cases} q  +  16p  = 1  \\ 9q + 4p = 1 \end{cases}

solving the system of linear equation will yield:

\displaystyle  \begin{cases} q   =  \dfrac{3}{35} \\ \\  p =  \dfrac{2}{35}  \end{cases}

substitute back:

\displaystyle  \begin{cases}  \dfrac{1}{ {a}^{2} }   =  \dfrac{3}{35} \\ \\   \dfrac{1}{ {b}^{2} }  =  \dfrac{2}{35}  \end{cases}

divide both equation by 1 which yields:

\displaystyle  \begin{cases}  {a}^{2}   =  \dfrac{35}{ 3} \\ \\    {b}^{2}   =  \dfrac{35}{2}  \end{cases}

substitute the value of a² and b² in the ellipse equation , thus:

\displaystyle  \frac{  {x}^{2} }{  \dfrac{35}{3}  }  +  \frac{{y}^{2} }{  \dfrac{35}{2}  }   = 1

simplify complex fraction:

\displaystyle  \frac{  {3x}^{2} }{ 35 }  +  \frac{{2y}^{2} }{  35  }   = 1

and we're done!

(refer the attachment as well)

8 0
3 years ago
Find the point of intersection of the pair of straight lines<br> Y= -7x - 4<br> -y = 8x + 9
Aleonysh [2.5K]

Answer:

(-5,31)

Step-by-step explanation:

See image.

4 0
3 years ago
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