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3 years ago

Is my answer on the photo correct?

Mathematics

1 answer:

vladimir2022 [97]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

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Can somebody help me find the perimeter of this figure?

lbvjy [14]

Answer: P = 64in,

Step-by-step explanation: P = 17 + 13 + 25 + 9

3 0

3 years ago

0.59 O 2/3 A. = B. > C. < D. none of the above

egoroff_w [7]

0.59 and 2/3

0.59
0.66

0.59 < 2/3

2/3 is greater than 0.59.

Answer :

6 0

3 years ago

Which of these number lines represents the difference -3-2

Yuki888 [10]

Answer:

Number line D

Step-by-step explanation:

That line goes from 0 to -3 and subtracts 2, as the equation shows.

6 0

3 years ago

Find the equation of ellipse passing throgh (1,4) and (-3,2)

irinina [24]

Answer:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

Step-by-step explanation:

we want to figure out the ellipse equation which passes through (1,4) and (-3,2)

the standard form of ellipse equation is given by:

$\displaystyle \frac{(x - h {)}^{2} }{ {a}^{2} } + \frac{(y - k {)}^{2} }{ {b}^{2} } = 1$

where:

(h,k) is the centre
a is the horizontal redius
b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

$\displaystyle \frac{ {x}^{2} }{ {a}^{2} } + \frac{{y}^{2} }{ {b}^{2} } = 1$

substituting the value of x and y from the point (1,4),we'd acquire:

$\displaystyle \frac{ 1}{ {a}^{2} } + \frac{16}{ {b}^{2} } = 1$

similarly using the point (-3,2), we'd obtain:

$\displaystyle \frac{ 9}{ {a}^{2} } + \frac{4 }{ {b}^{2} } = 1$

let 1/a² and 1/b² be q and p respectively and transform the equation:

$\displaystyle \begin{cases} q + 16p = 1 \\ 9q + 4p = 1 \end{cases}$

solving the system of linear equation will yield:

$\displaystyle \begin{cases} q = \dfrac{3}{35} \\ \\ p = \dfrac{2}{35} \end{cases}$

substitute back:

$\displaystyle \begin{cases} \dfrac{1}{ {a}^{2} } = \dfrac{3}{35} \\ \\ \dfrac{1}{ {b}^{2} } = \dfrac{2}{35} \end{cases}$

divide both equation by 1 which yields:

$\displaystyle \begin{cases} {a}^{2} = \dfrac{35}{ 3} \\ \\ {b}^{2} = \dfrac{35}{2} \end{cases}$

substitute the value of a² and b² in the ellipse equation , thus:

$\displaystyle \frac{ {x}^{2} }{ \dfrac{35}{3} } + \frac{{y}^{2} }{ \dfrac{35}{2} } = 1$

simplify complex fraction:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

and we're done!

(refer the attachment as well)

8 0

3 years ago

Find the point of intersection of the pair of straight lines Y= -7x - 4 -y = 8x + 9

Aleonysh [2.5K]

Answer:

(-5,31)

Step-by-step explanation:

See image.

4 0

3 years ago

Is my answer on the photo correct? ​

Is my answer on the photo correct?