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galben [10]
3 years ago
14

Are 3x+1 and 3x equivalent Yes or No Explain why they are or aren't equivalent!!!

Mathematics
1 answer:
snow_tiger [21]3 years ago
4 0

Answer:

NO

Step-by-step explanation:

3x + 1 and 3x are different

Step 1:  Lets put some numbers instead of x

x = 1

y = 3x + 1

y = 3(1) + 1

y = 4

y = 3x

y = 3(1)

y = 3

SEE IT IS DIFFERENT.

Attached are the graphs

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How many lots of 10 second are there in 10 minutes
Vlad [161]

Answer:

60

Step-by-step explanation:

We can easily solve this by finding out how many 60 seconds are in 10 minutes, and then dividing by 10.

To do that, multiply 60 seconds by 10, since there are 60 seconds in each minute.

60*10=600. There are 600 seconds in ten minutes.

Now, divide by 10.

600/10=60

There are 60 intervals of 10 seconds in 10 minutes.

Hope this helps!

7 0
2 years ago
Candidate carson received 2310 votes 55% of the total how many total votes were cast
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Step-by-step explanation: is what i got maybe wrong

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3 years ago
I have 4 sides that are the same length but no right angles
Marysya12 [62]

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8 0
3 years ago
Read 2 more answers
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
Please help and show work!!
Advocard [28]

1/3x + y = -2

-1/3x         -1/3x

y = -1/3x-2

4 0
3 years ago
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