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artcher [175]
3 years ago
7

PLEASEEEEEE HELPPPP!!!!

Mathematics
2 answers:
pogonyaev3 years ago
6 0
I believe this would be correct.

LUCKY_DIMON [66]3 years ago
6 0
This would be about correct!

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the radius of wheel of a bicycle is 40 cm. taking pie =3.14, a)find tthe circumference of the wheel.b) find the distance covered
monitta

Answer:

a)=251.2 cm    b)=50240 cm

Step-by-step explanation:

a) The formula for calculating the circumference of a circle is c=d*pie, where D is the diameter of the circle.

Therefore, C = 2 * 40 * 3.14 = 251.2 cm

b) The distance covered by 200 revolutions of the wheel is 200 times the circumference, 200*251.2=50240 cm.So to think about this we can assume that there is a point A on the wheel, the distance that point A travels when it rotates 200 times.

6 0
3 years ago
I need help with adding complex numbers
Usimov [2.4K]

For example:

Find: (3-i)+(2+3i) by graphing

Step 1: Graph 3-i and 2+3i on the complex plane. Connect each of these numbers to the origin with a line segment.


4 0
3 years ago
What is the multiplicative inverse of 1/16 ?
andrey2020 [161]

Answer:

16/1 I think

Step-by-step explanation:

8 0
3 years ago
In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
2 years ago
Please help! I don’t know how to make the square roots equal to each other but I understand the other steps... kind of.
katovenus [111]

Answer:

Step-by-step explanation:

4 0
3 years ago
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