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2 years ago

What is the x^3=15 bc i duno

Mathematics

2 answers:

MakcuM [25]2 years ago

6 0

Answer:

2.466...

Step-by-step explanation:

You must find the cube root of 15.

It's 2.466...

hope it helps! :-)

Oxana [17]2 years ago

6 0

The answer is x = the cube root of 25.

Simple, what you need to do is move the cube on x to the other side of the equal, therefore making it cube root. And that's the answer.

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Which of the following are solutions to the equation below?

anastassius [24]

Answer:

C and F

Step-by-step explanation:

Given

(3x - 5)² = 19 ( take the square root of both sides )

3x - 5 = ± $\sqrt{19}$ ← note plus or minus

Add 5 to both sides

3x = ± $\sqrt{19}$ + 5 ( divide both sides by 3 )

x = ± $\frac{\sqrt{\sqrt{19}+5 } }{3}$

Separating the solutions

x = $\frac{\sqrt{19}+5 }{3}$ → C

x = $\frac{-\sqrt{19}+5 }{3}$ → F

4 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

Find the inverse, please help.

igomit [66]

Replace f(x) with y

Y = 2x -5

Swap roles of x

X= 2y-5

5+x =2y

Divide by 2

5+x /2 = y

Replace y with inverse f^-1(x)

Answer= f^-1(x) = 5+x / 2

6 0

2 years ago

Megan took a cab ride and was charged a fare of $1.50 per mile and an additional charge of $5 for her luggage. If Megan traveled

____ [38]

For example let's say Megan has to pay the cab driver $50. Here's the equation 50=1.50x + 5 First you want to get x by itself on one side. So subtract 5 on both sides 50=1.50x + 5 -5 -5 --------------------------- 45=1.50x Now that you have x on one side; however, you want to divide to get the answer. 45=1.50x ----------------------- 1.50 x = 30 So if Megan pay $50 that mean she rode 30 miles ~by the way I'm sorry if you are looking at the answers and it isn't in the right place, I'm answering this on a tablet~

7 0

2 years ago

Find the range for the set of data 24, 30, 17, 22, 22

OverLord2011 [107]

$\huge\text{Hey there!}$