Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
Answer:
Answer is A. 36x-11y
Step-by-step explanation:
34x-12x+14x-18y+7y
=22x+14x-18y+7y
=36x-11y
Cone's volume is

where S - surface area, h - height
Surface area =

r = 18/2=9
h= 14
π = 3.14

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Answer:
10 times
Step-by-step explanation:
3 nonbank atm withdrawals costs 5.25 and the total is 8.25 meaning the remaining must add up to 3. And if you multiply .3 by 10 it gives you 3
Hi
The answer is : 14s^133t^5u^144v^2
Good luck :) You can trust my answer