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Komok [63]
3 years ago
14

Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

y(x)=tan(-log(cos(x))+\frac{\pi }{3} )

Step-by-step explanation:

Rewrite the equation as:

\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)

Isolating \frac{dy}{dx}

\frac{dy}{dx} =tan(x)+tan(x)*y^{2}

Factor:

\frac{dy}{dx} =tan(x)*(1+y^{2} )

Dividing both sides by (1+y^{2} ) and multiplying them by dx

\frac{dy}{1+y^{2} } =tan(x)dx

Integrate both sides:

\int\ \frac{dy}{1+y^{2} } = \int\ tan(x)  dx

Evaluate the integrals:

arctan(y)=-log(cos(x))+C_1

Solving for y:

y(x)=tan(-log(cos(x))+C_1)

Evaluating the initial condition:

y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)

\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1

Converting 60 degrees to radians:

60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}

Replacing C_1 in the diferential equation solution:

y(x)=tan(-log(cos(x))+\frac{\pi }{3} )

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