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3 years ago

How many distinct arrangements can be formed from all the letters of "students"? Please show your work. Thanks!

Mathematics

1 answer:

topjm [15]3 years ago

6 0

There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).

First find the number of arrangements that can be made using 8 letters.

This is 8! which is:

8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320

Now there are 2 s's and 2 t's find the number of arrangements of those:

S = 2! = 2 x 1 = 2

T = 2! = 2 x 1 = 2

Now divide the total combinations by the product of the s and t's:

40,320 / (2*2)

= 40320 / 4

= 10,080

The answer is A. 10,080

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Two thirds equals 18 over x plus 5

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First, I would multiply the (x+5) over

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Second, I would Divide by 2/3 (which is the same as multiplying by the reciprocal 3/2)

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3 years ago

Three vertices of a rectangle have coordinates (3,4), (5,-4), and (-7,-7). What is the y coordinate of the fourth vertex?

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3 years ago

A movie theater has been charging $10.00 per person and selling about 500 tickets on a typical weeknight. After surveying their

kifflom [539]

Answer:

$p(x) = -0.01x + 15$

Step-by-step explanation:

Given

Let x represent the number of tickets, and p the charges

$(x_1,p_1) = (500,10)$

A reduction of 50c gives an increment of 50 tickets.

This gives:

$(x_2,p_2) = (500+50,10-0,5)$ ---- $50c = \$0.5$

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Required

Determine the demand function

First, calculate the slope:

$m = \frac{p_2 - p_1}{x_2 - x_1}$

$m = \frac{9.5 - 10}{550-500}$

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$m = -0.01$

So, the equation is:

$p = m(x - x_1) + y_1$

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$p(x) = -0.01x + 15$

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3 years ago

A sample of 4 different calculators is randomly selected from a group containing 19 that are defective and 36 that have no defec

Liono4ka [1.6K]

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3 years ago

4.36 Stats final scores. Each year about 1500 students take the introductory statistics course at a large university. This year

velikii [3]

Answer:

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Step-by-step explanation:

We use the Pearson Mode Skewness to solve this question. It states that:

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If the median is lower than the mean, the distribution is right-skewed.

If the median is the same as the mean, the distribution is symmetric.

In this problem, we have that:

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Median higher than the mean

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3 years ago

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