Hi there!
There are 3 parts to this equation:
f(x)
f(x+1)
4f(x)
We must first determine these three parts separately.
<u>1) f(x)</u>
We're given that 
:
⇒ :
<u>2) f(x+1)</u>
Now, we must find f(x+1). To do so, add 1 to x in the original function :
⇒ 
<u>3) 4f(x)</u>
To find 4f(x), multiply the original function by 4:
:
<u>4) Put it all together</u>
Now, plug each of the three parts into the equation :
Factor the left side
Divide both sides by 3^x
Because this equation is true, is therefore true.
I hope this helps!
Answer:
w= 1
Step-by-step explanation:
hope this helps :)
Area=legnth times width or
a=lw
if w=4/5l
and a=320 then subsitute 320 for a dn 4/5l for w
320=4/5l times l
multiply both sides by 5 to clear fraction
1600=4l times l
ad like terms
1600=4l^2
subtract 1600 from both sides
0=4l^2-1600
try and factor because if you have xy=0 then x and/or y=0 so
difference of 2 perfect squares where
if you have a^2-b^2 then that equals(a-b)(a+b) so
0=(2l)^2-(40)^2=(2l-40)(2l+40)
so 2l-40=0
add 40 to both sides
2l=40
divide by 2
l=20
if
2l+40=0
subtract 40 from both sides
2l=-40
divide 2
l=-20
since meausrements of real objects cannot be negative, wediscard this number
l=20 is thhe true legnth s
subsitute
w=4/5l
w=4/5(20)
w=80/5
w=16
legnth=20
width=16
Answer:
89·98 mph
Step-by-step explanation:
First, we get the circumference of the tires:
Circumference = 
× (radius × 2)
Circumference = 3.142 × (1·5 × 2)
Circumference = 3·142 × 3
Circumference = 9·426 ft
The circumference of the tire is equal to one round.
1 round = 9·426 ft
840 rounds = ?
We cross multiply to get the length that the tires would cover in a minute
= <u>840 × 9·426</u>
1
1 minute = 7917·84 ft
60 minutes = ?
<u>60 × 7917·84</u>
1
= 475070·4 ft
5280 feet = 1 mile
475070·4 feet = ?
<u>475070·4 × 1</u>
5280
475070·4 ÷ 5280 = speed of the car in mph
89·97545
Round this off to 2 decimal places...
= 89·98 mph
hope this helps! =)
True, 0.92 is positive and an r-value of more than or equal to 0.75 will mean it is strong
