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2 years ago

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2 employees share 1 job. A girl works Monday Wednesday and Fridays. A boy works Tuesdays and Thursdays. The job pays an annual s

alary of $28,602. What annual salary does each employee earn?

1 answer:

luda_lava [24]2 years ago

8 0

I would think $<span>14,301. If is is a shared salary then just divide by two since there are two people.</span>

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Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

$CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}$

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

$CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}$

Given:

$\bar x=27.97\\s=10.04\\n=25\\t_{\alpha /2, (n-1)}=t_{0.01/2, (25-1)}=t_{0.005, 24}=2.797$

*Use the <em>t</em>-table for the critical value.

Compute the 99% confidence interval as follows:

$CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)$

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

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3 years ago

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Answer:

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