(base x height)/2 good luck young one
see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in
Answer:
(5,6)
Step-by-step explanation:
I'm guessing you mean the coordinates for the point where the lines intersect
Answer:
adout 53 Years old
Step-by-step explanation:
2. = 6=12=32. 32/2= 16
5.3=16=32= 16/3=5.333...
5.3x10=S3.3
so adout 53 Years old
Answer:
6a. 26
6b. 60%
6c. 33.3% or just one-thrid
7. 80.925 rounded is $80.93
8. 240
9. 25
10. 54%
Step-by-step explanation:
brainliest please!