Please help me solve this 200(20)^x>500x+400

1 answer:

s2008m [1.1K]3 years ago

6 0

Hi there!

200(20)^x > 500x + 400

Let's find the critical points of the inequality

200(20^x) = 500x + 400

Now we can divide both sides by 200

(200(20^x))/200 = (500x + 400)/200

20x^x = 5/2 x + 2

There are no critical points.

Thus,

The answer is: No solution

As always, it is my pleasure to help students like you.

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