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nika2105 [10]
3 years ago
7

The fifth root of x to the fourth power times the fifth root of x to the fourth power

Mathematics
2 answers:
drek231 [11]3 years ago
8 0
Remember
(√a)(√b)=√(ab)
and
(x^m)(x^n)=x^{m+n}
so

( \sqrt[5]{x^4})( \sqrt[5]{x^4}  )=
\sqrt[5]{(x^4)(x^4)}
4+4=8
\sqrt[5]{x^8}=
( \sqrt[5]{x^5})( \sqrt[5]{x^3}  )=
x\sqrt[5]{x^3}

valentinak56 [21]3 years ago
8 0
5th root of x to the 4th times 5th root of x to the 4th = 5th root of x to the 8th
Reduces to x times 5th root of x to the 3rd
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Mr.Cereola multiples some number x by some number y and then raises the product to the fourth power. If x=4 and y=3 find the end
sergij07 [2.7K]

Answer:

20736

Step-by-step explanation:

xy^4 = z

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(4*3)^4=z

12^4=z

z=20736

3 0
3 years ago
Maddie and her friends are making s'mores over the campfire. they have a bag of 48 marshmallows, 2 packs of graham crackers cont
VladimirAG [237]

The answer would be 16 S'mores and the limiting reactant would be the grahams.


(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)


Limiting reactant would be the reactant that runs out first.


Let's take your problem into account and see what we have:

48 marshallows

32 grahams (2 x 16 per pack)

45 chocolate pieces (5 x 15 pieces per bar)


Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.

The maximum yield of marshmallows is 48.

The maximum yield of chocolate is 45.


Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.

8 0
3 years ago
3. A mysterious metal medallion has a mass of 3,088 grams. Water is poured into a graduated glass container with a 10-by-10 cm s
Gekata [30.6K]

Step-by-step explanation:

Volume of displaced water = (10cm)(10cm)(1.6cm)

= 160 cm^3

density = mass/vol of displaced water

= 3088 grams/160 cm^3

= 19.3 g/cm^3

P.S. This is most likely a pure gold medallion.

6 0
2 years ago
Find the measure of angle r
guapka [62]
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5 0
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What is pie exactly equal to?
natta225 [31]
Ummmm

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i think its right
3 0
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