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satela [25.4K]
3 years ago
10

What is the solution to the system of equations represented by these two lines?

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0
The answer is c (2,3)
borishaifa [10]3 years ago
7 0
C. (2,3) is the correct answer

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-4 3/5 divided by 1 1/5 as a mixed number or simplified
WITCHER [35]
-23 over 5 ÷ 11 over 5
-23 × 5 over 5 × 5
-115 over 55


Therefore, your answer would be: -2 and 1 over 11
4 0
4 years ago
Read 2 more answers
PLEASE HELP
lozanna [386]

Answer:

-200 | -500 | -500-(-200) | -300

-200 | -0      | 0 -(-200)     |  200

Step-by-step explanation:

8 0
3 years ago
Pls can anyone give me tips for studying when I'm high-school ​
dimulka [17.4K]

Answer:

take a break from social media , find a peaceful spot to study ,be engaged , take notes and listen during discussion make use of ur extra time wisely

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5 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the heig
siniylev [52]
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.

answer: 4.8
6 0
4 years ago
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