Answer:
y= −2/3x+−20/3
heart if it helped you brain if im cool
Answer:
L = 4.103
Step-by-step explanation:
we have length of curve
![L = \int\limits^b_a {\sqrt{(f'(x))²+1} } \, dx](https://tex.z-dn.net/?f=%20L%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Csqrt%7B%28f%27%28x%29%29%C2%B2%2B1%7D%20%7D%20%5C%2C%20dx%20)
where ![f(x) = d/dx(3*in(x)) = 3/x](https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20d%2Fdx%283%2Ain%28x%29%29%20%3D%203%2Fx%20)
substituting for f(x), we have ![L = \int\limits^5_2 {\sqrt{(3/x)²+1} } \, dx](https://tex.z-dn.net/?f=%20L%20%3D%20%5Cint%5Climits%5E5_2%20%7B%5Csqrt%7B%283%2Fx%29%C2%B2%2B1%7D%20%7D%20%5C%2C%20dx%20)
(since the limit is 2≤ x ≤5)
solving, ![L = \int\limits^5_2 {\sqrt{9/x²+1} } \, dx](https://tex.z-dn.net/?f=%20L%20%3D%20%5Cint%5Climits%5E5_2%20%7B%5Csqrt%7B9%2Fx%C2%B2%2B1%7D%20%7D%20%5C%2C%20dx%20)
Simplifying this integral, we have
L = 4.10321
Im thinking it's false. 18 isn't even between 4 and 9.
From the computation done, the total kilometers that he uses last month will be 262.8 kilometers.
The total length of a trip to and from work is 14.6 kilometers and last month, Jeremiah worked 18 days.
Therefore, the kilometers that he rode his bike to and from work last month will be;
= 14.6 × 18.
= 262.8 kilometers.
Learn more about equations on:
brainly.com/question/13763238
-- After dog ate 1/2 of the collection, there were 29 remaining.
-- Just before dog came along, there were (2 x 29) = 58 cards.
-- That was after Dan added 5 new ones.
-- Before he added the 5 new ones, there were (58 - 5) = 53 cards.
-- When this story began, Dan had <em>53 cards</em>.