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Paha777 [63]
3 years ago
7

Find the value of the length x rounded to 1 DP.

Mathematics
2 answers:
Setler79 [48]3 years ago
8 0
DP-28 Has 51 damage on player
bagirrra123 [75]3 years ago
5 0

Length of x is 98.2 m

<u>Step-by-step explanation:</u>

Step 1:

Use the trigonometric ratio tan 27° to find the common side of both the right angled triangles.

tan 27° = opposite side/adjacent side = opposite side/9

∴ Opposite side = 9 tan 27° = 9 × - 3.27 = -29.46 m

Step 2:

Use this side and trigonometric ratio cosine to find the value of x.

cos 49° = adjacent side/x = -29.46/x

∴ x = -29.46/cos 49° = -29.46/0.30

     = 98.2 m (negative value neglected)

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Trigonometry<br> Special Right Triangles<br> Find the exact value of sec 60* - cosec 30* - sin 0*.
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0

Step-by-step explanation:

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A particular psychological test is used to measure need for achievement. The average test score for all university students in O
Angelina_Jolie [31]

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Only B and C are always true.

Step-by-step explanation:

To analyse which statements are always true, we go through the process of finding confidence intervals for sample means, from the start.

Confidence Interval = (Sample mean) ± (Margin of error)

From this expression, it is evident that the margin of error determines how wide the confidence interval would be.

Sample Mean = 110 (given)

Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

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The critical value usually varies at different confidence levels and degree of freedoms.

The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

σₓ = σ/√n

where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

Or the sample size might be high enough to make the standard error of the mean to be eventually small and lead to a small margin of error and the condidence interval will not contain 115.

The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

Then from σₓ = σ/√n,

n = sample size, a large sample size means a more narrow confidence interval and a small sample size means a wider sample size. This proves statement C.

The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

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