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3 years ago

PLEASE HELP! here is the math problem.

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

5 0

The first option: Additive Inverse Property is the right answer

Step-by-step explanation:

Additive inverse can be defined as: " For every number x, there exists a number -x, the sum of both is zero"

Additive Inverse Property:

Additive inverse property states that the sum of a number and it's additive inverse is zero

i.e.

$a + (-a) = 0$

In the given proof, the same property is used in the step:

$b+a+(-a) = b+[a+(-a)]\\b+a+(-a) = b+0$

Hence,

The first option: Additive Inverse Property is the right answer

Keywords: Proves, Additive inverse

Learn more about additive inverse at:

#LearnwithBrainly

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Grandma baked 96 cookies and gave them to her grandchildren. one of the grandchildren, cindy, received 5 fewer cookies than she

professor190 [17]

If all the h grandchildren will receive equal amounts of cookies then, the number of cookies that each will receive is,
96/h
Then, Cindy will receive
96/h - 5 candies

7 0

3 years ago

Read 2 more answers

A recipe requires 1/4 lb of onions to make 3 servings of soup. Mark has 1 1/2 lb of onions. How many servings can Mark make?

Oxana [17]

⓵ You have to do a cross product in order to find your answer :

1/4 lb → 3 servings
1 ½ lb → × servings

(3 x 1 ½) ÷ 1/4 = (3 x 1,5) ÷ 0,25

⓶ Now you need to solve the equation :

(3 x 1,5) ÷ 0,25

↓

(4,5) ÷ 0,25

↓

4,5 ÷ 0,25 = 18

Which means that your final answer is that Mark can make 18 servings with 1 ½ lb of onions!

I hope this helped! ☻

6 0

3 years ago

Evaluate the expression, xz- y, if x=3,y=6, and z =7

avanturin [10]

3*7-6
21-6=15
15 is the answer

4 0

3 years ago

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago

Identify like terms. (a) 3x, 4y, -2x help

kkurt [141]

3x and -2x are like terms because they both have the variable X

6 0

3 years ago