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ruslelena [56]
3 years ago
12

Grandma baked 96 cookies and gave them to her grandchildren. one of the grandchildren, cindy, received 5 fewer cookies than she

would have received had all of the cookies been evenly divided among the h grandchildren. how many cookies did cindy receive? write your answer as an expression.
Mathematics
2 answers:
professor190 [17]3 years ago
7 0
If all the h grandchildren will receive equal amounts of cookies then, the number of cookies that each will receive is,
                                   96/h
Then, Cindy will receive 
                                      96/h - 5 candies
astra-53 [7]3 years ago
7 0

Answer: Cindy received 96/h-5 cookies

Step-by-step explanation:

Hi, to write the expression we have to analyze the information given:

If all the cookies (96) would have been evenly divided among the h grandchildren, each child should have gotten 96/h cookies.

Cindy received 5 fewer cookies than that number.

So, mathematically speaking: 96/h - 5

In conclusion, Cindy received 96/h-5 cookies. Where h is the number of grandchildren.

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What is the measure of ABC?<br> A. 130<br> B. 85<br> C.40<br> D.170
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Step-by-step explanation:

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0.45, 4, 2, 1.5

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8 0
2 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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