Ask question

Ask question

All categories

3 years ago

11

The sum of the ages of Michael and Leah is 71 years. 10 years ago, Michael's age was 2 times Leah's age. How old is Michael now?

1 answer:

telo118 [61]3 years ago

5 0

Answer:

44 years

Step-by-step explanation:

The sum of the ages of Michael and Leah is 71 years. 10 years ago, Michael's age was 2 times Leah's age. How old is Michael now?

Let Michael age = x , Leah = y

x+ y = 71 ....... ..(1)

10 year ago

Michael = x -10

Leah = y - 10

Michael = 2×leah

x - 10 = 2(y-10)

x - 10= 2y - 20

x - 2y = -20+10

x - 2y = -10 ...........(2)

x + y = 71 ......... (1)

Solve simultaneously using elimination method, subtract 1 from 2

-2y - y = -10-71

-3y = -81

Divide both sides by -3

y = -81/-3

y =27

x+y = 71

Put y =27

x+27= 71

x = 71 -27

x =44 years

Therefore Michael is 44years

I hope this was helpful, please mark as brainliest

You might be interested in

Simplify the expression write your answer as a power

Ira Lisetskai [31]

Answer:

$3^{4}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$ , then

3² × 3²

= $3^{(2+2)}$

= $3^{4}$

7 0

2 years ago

[GEOMETRY] please help, i keep getting 622, thats not one of the answers

Flauer [41]

It is 622 . 622 is 198*3.14

6 0

2 years ago

50 points in reward

Kay [80]

Answer:

your answer to your problem is D

8 0

2 years ago

(0,-2),(4,-162) exponential function

Luda [366]

Yessssss yessssss yesssss

4 0

3 years ago

Find the equation of the tangent line to the curve <br> 2exy=x+y at (0,2).

DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function = f(x,y) = $2e^{xy} -x-y=0$ ...(i)

Differentiating equation (i) with respective to 'x' , we get

$2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0$

apply formula

$\frac{d}{dx} (UV) = UV^{l} +V U^{l}$

<u><em>step(ii):-</em></u>

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0$

⇒ $2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0$

Taking common d y/d x

$(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))$

$\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}$

put At (0,2)

$\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3$

slope of the curve m = 3

<u><em>Step(iii)</em></u>:-

The equation of the tangent line to the curve

$y-y_{1} =m(x-x_{1} )$

y - 2 = 3 ( x - 0 )

3 x - y = 2

<u><em>Final answer:-</em></u>

The equation of the tangent line to the curve

3 x - y = 2

8 0

2 years ago