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Radda [10]
3 years ago
8

How to turn Ratio as a fraction

Mathematics
1 answer:
beks73 [17]3 years ago
7 0
Convert the ratio to a fraction by making the left side of the ratio the numerator and the right side the denominator.
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A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible
steposvetlana [31]

Answer:

AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}

BA is:

BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

8 0
3 years ago
Solve the system by the substitution method. Show your work.<br> 2y - x = 5<br> x^2 + y^2 - 25 = 0
Elza [17]
2y - x = 5
x^2 + y^2 - 25 = 0

x = 2y - 5

(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4

x = 2y - 5 , when y = 0
x = - 5

x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
6 0
3 years ago
What is the scale factor from figure A to figure B?
SCORPION-xisa [38]

Answer:

Figure A sides are 1/4 the size of Figure B

The top of Figure A = 4, the top of Figure B = 1.

Divide 1 by 4 to get the scale factor, which is 1/4 as a fraction or 0.25 as a decimal.

Step-by-step explanation:

3 0
3 years ago
Josh has 4 times as many pears as leya, who has one half as many pears as amy. If josh has 32 pears how many does amy have?
arlik [135]
<h3>The number of pears Amy has is 16.</h3>

Step-by-step explanation:

Let J represent the number of pears Josh has.

Let L represent the number of pears Leya has.

Let A represent the number of pears Amy has.

From the question given above,

Josh (J) = 4 × Leya (L)

J = 4L ....... (1)

Leya (L) = ½ × Amy (A)

L = ½A ........ (2)

Next, we shall determine the number of pears Leya has. This can be obtained as follow:

From equation 1

J = 4L

But

Josh (J) = 32 pears

Thus,

32 = 4L

Divide both side by 4

L = 32 / 4

<h3>Leya (L) = 8 pears </h3>

Finally, we shall determine the number pears Amy has. This can be obtained as follow:

From equation 2

L = ½A

But

Leya (L) = 8 pears

Thus,

8 = ½A

Cross multiply

A = 8 × 2

<h3>Amy (A) = 16 pears </h3>

Therefore, Amy has 16 pears.

Learn more: brainly.com/question/20971657

6 0
3 years ago
Read 2 more answers
7t+2r-3t+r what is the answer
Troyanec [42]
This simplifies to 4t+3r
8 0
3 years ago
Read 2 more answers
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