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3 years ago

Solve the equation for x. 2(x-2) + 6 = 2

Mathematics

2 answers:

padilas [110]3 years ago

8 0

Answer:

x=0

Step-by-step explanation:

Tpy6a [65]3 years ago

6 0

Answer:

x=0

Step-by-step explanation:

2x-4+6=2

2x+2=2

2x=0

x=0

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Find the value of c, rounded to the nearest tenth <br> A. 11<br> B. 14.3<br> C. 37.6<br> D. 7.4

Helga [31]

Answer:

D. The correct value of c = 7.4

Step-by-step explanation:

According to Tangent-Secant theorem:

"When a tangent and a secant are drawn from one single external point to a circle, square of the length of tangent segment must be equal to the product of lengths of whole secant segment and the exterior portion of secant segment."

Here, the external length of tangent segment = 10

Also, the length of internal segment is 14 and c.

So, by the SECANT THEOREM:

$(10)^2 = 14 \times c\\\implies c = \frac{100}{14} = 7.14$

or, c = 7. 1428

Now, rounding off the value of c = 7. 14 to the nearest tenth, we get

c = 7. 4

Hence the correct value of c = 7.4

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What percent of $90 = $45

Lynna [10]

45 is exactly half of 90
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Cuanto es 120% en fraccion

kow [346]

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2 years ago

What is the factored form of x^3 -1

lianna [129]

Answer:

The factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

Step-by-step explanation:

Given the expression

$x^3-1$

Rewrite 1 as 1³

$=x^3-1^3$

$\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)$

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

$=\left(x-1\right)\left(x^2+x+1\right)$

Thus, the factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

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