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SIZIF [17.4K]
3 years ago
14

For a line perpendicular to the line y = 2x - 3 through the point (4,-6)

Mathematics
2 answers:
Romashka [77]3 years ago
6 0

Answer:

y=2x-14

Step-by-step explanation:

y=mx+c

-6=2(4)+c

-6=8+c

-6-8=c

c=-14

y=mx+c

y=2x-14

leonid [27]3 years ago
3 0
I got you this is the answer Y+6=-1/2(x-4)
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3 years ago
Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
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a × c = 3 × (-6) = -18

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x + 1 = 0

Therefore:

x = 2

OR

x = -1

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We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
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