1. the graph of 2x + 1 = y for all real numbers will be a line. the graph with the restricted domain will be a line segment meaning it has endpoints (1, 3) and (4, 9).
2. is open ended, meaning you can make A, B, C anything you want as long as what they specify is met. (a) A = 0 (0)x + By = C let's make B = 1 and C = 5 y = 5
(b) B = 0 Ax + (0)y = C let's make A = 1 and C = 5 x = 5
(c) C = 0 Ax + By = 0 let's make both A and B = 1 x + y = 0
3. plot both intercepts (x on x-axis, y on y-axis) then draw a line through the dots.
4-7. linear equations do not have exponents on any of the variables. 1/y is the same as y^(-1) so both 4 and 7 are non-linear.
8-13. you will have to graph these. put them in slope intercept form: y = mx+b if they're not already , plot the y-intercept first (0, b) then use the slope m draw the line by going rise over run.
example 13. 3x + 4y = 12 4y = -3x + 12 y = (-3/4) + 3 plot (0,3) go down -3 , right 4 make a point. reverse from (0,3) go up 3 left -4 and make a point. connect with line.
