Answer:
2c^2 - 2c - 3
Step-by-step explanation:
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Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:
2 + 4c and -4c^2 + 4 Then we have:
-4c^2 + 4c + 6
We should reduce this by factoring -2 out of all three terms:
2c^2 - 2c - 3 This is the desired quadratic in standard form.
Answer:
. Name all horizontal and vertical intercepts of the graph.
Step-by-step explanation:
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.