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3 years ago

What are the answers for both of these what are zeros help

Mathematics

1 answer:

Archy [21]3 years ago

4 0

Graph 5- e)
graph 6- b)

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Solve the linear system:<br> y=4x-7 <br> y=4x+4

STALIN [3.7K]

Answer:

Hi! The correct answer is No solutions!

Step-by-step explanation:

<em><u>~solve for the first variable in one of the equations, then substitute the result into the other equation~</u></em>

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3 years ago

Write an equation of the circle with center (-2, 7) and radius 9.

Andrei [34K]

(x+2)^2 + (y-7)^2 = 9^2

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2 years ago

A. Find value of x and KL if K is between J and L.

MrRa [10]

Answer:

x=3

Step-by-step explanation:

If k is between J and L, then

JK + KL = JL

2x+11 + (3x) = 13x-13

Combine like terms

5x +11 = 13x -13

Subtract 5x from each side

5x-5x+11 = 13x-5x-13

11 = 8x-13

Add 13 to each side

11+13 = 8x-13+13

24 = 8x

Divide by 8

24/8 = 8x/8

3 =x

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3 years ago

Find the slope and y intercept of the line y=7/5x-3 5/7; 3 3; 7/5 7/5;-3 -3; 7/5

7nadin3 [17]

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

y = 7/5x - 3

Comparing with the above formula

<h3>Slope / m = 7/5</h3><h3>c/ y intercept = - 3</h3>

Hope this helps you

8 0

2 years ago

Read 2 more answers

The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation: $V(t)= 42(1-e ^{1.5t} ) +36$ is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

$V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85$

V(12) = $V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00$

b) Find derivative for V

$V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}$

c) When V(t) = 75

$V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639$

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

3 0

2 years ago