Ajajajsjsjjsjsjdjdjdjdjd sorry but I need more points
Thanks for posting your question here. The answer to the above problem is x = <span>48.125. Below is the solution:
</span>
x+x/7+1/11(x+x/7)=60
x = x/1 = x • 7/7
x <span>• 7 + x/ 7 = 8x/7 - 60 = 0
</span>x + x/7 + 1/11 <span>• 8x/7 - 60 = 0
</span>8x <span>• 11 + 8x/ 77 = 96x/ 77
</span>96x - 4620 = 12 <span>• (8x-385)
</span>8x - 385 = 0
x = 48.125
If they're integers, that means they can't be fractions (such as 15/2 and 2).
So the only couples of integers that, when multiplied, result in 15 are:
1 and 15
5 and 3.
(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.
The least possible sum of a and b is 8.
reduce the index of the radical and exponent with 3, rhen you get your answer, 6
