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Tom [10]
3 years ago
10

What is the square root of 81

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
4 0

9 hope this helps you

Semenov [28]3 years ago
4 0

Explanation: A square root of a number is one of the number's two equal factors.

You can also multiply by the numbers.

9*9=81

Then, dividing into the groups of 81.

81/9=9

\sqrt{9^2=9*9=81}

<em><u>9 is the square root of 81.</u></em>

Hope this helps!

Thank you!

Have a great day!

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The water level in a tank can be modeled by the function h(t)=8cos(pi t /7)+11.5, where t is the number of
denis23 [38]

Answer:

NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height

Step-by-step explanation:

Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero

Velocity is the change in distance with respect to time.

V = {d(h(t)}/dt = -8π/7sin(πt/7)

At maximum height, -8π/7sin(πt/7) = 0

-Sin(πt/7) = 0

sin(πt/7) = 0

Taking the arcsin of both sides

arcsin(sin(πt/7)) = arcsin0

πt/7 = 0

t = 0

This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height

4 0
3 years ago
I am confused about how to do this problem and I don't think it should be hard, but I just don't know how to approach it, so if
solniwko [45]

Answer:

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) (0.875, 0.676)

d) (0, 1.235)

Step-by-step explanation:

Set each term in the numerator and denominator equal to 0 and find r.

In the numerator:

r = 7/8, 5/9, or 6

In the denominator:

r = 9/5, 7/8, or -3

Zeros in the numerator that aren't in the denominator are r-intercepts.

Zeros in the denominator that aren't in the numerator are vertical asymptotes.

Zeros in both the numerator and the denominator are holes.

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) Evaluate m(r) at r = 7/8.  To do that, first divide out the common term (-8r + 7) from the numerator and denominator.

m(r) = (-9r+5)² (r−6)² / ( (-5r+9)² (r+3)² )

m(⅞) = (-9×⅞+5)² (⅞−6)² / ( (-5×⅞+9)² (⅞+3)² )

m(⅞) = (-23/8)² (-41/8)² / ( (37/8)² (31/8)² )

m(⅞) = (-23)² (-41)² / ( (37)² (31)² )

m(⅞) = 0.676

The hole is at (0.875, 0.676).

d) Evaluate m(r) at r = 0.

m(0) = (-9×0+5)² (0−6)² / ( (-5×0+9)² (0+3)² )

m(0) = (5)² (-6)² / ( (9)² (3)² )

m(0) = 1.235

The m(r)-intercept is (0, 1.235).

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Answer:

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Cross Multiply

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Answer:

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Step-by-step explanation:

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