Answer: 3H+4C<_ 30
The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.
Step-by-step explanation:
Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.
Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:
Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?
No, because if you plug in the value for H and C:
3H + 4C<_ 30
3(5) + 4(4) <_30
15 + 16 <_ 30
31 <_ 30; false
Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.
No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Answer:
Step-by-step explanation:
Take the area of the yard and subtract from it the area of the pool. In quadratic form, the area of the pool is
Subtracting the area of the pool from the area of the yard:
Since the negative in front of the parenthesis will change the signs inside:
Combine like terms to get the area left after the pool goes in:
Answer: Fourth option: y^2=9^2+19^2-2(9)(19) cos(41°)
The law of cosines to solve for one side is:
c^2=a^2+b^2-2ab cos C
We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)
In this case c=y, a=9, b=19, and C=41°, then:
y^2=9^2+19^2-2(9)(19) cos (41°)
I’m fairly sure it’s 2N as N is the amount of people. Say there were 100 people that turned up, you would need 200 party favours (obviously because it’s two each) so 2N is 2 x 100 = 200
I’m sorry if it’s wrong! That’s what I would have put :)
Answer:
No Answers
Step-by-step explanation:
You have yet to provide some kind of questions for us to solve for these promised points.
