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2 years ago

PLZ HALP ANSWER QUICK FIRST CORRECT ANSWER GETS BRANLIEST

Mathematics

2 answers:

ehidna [41]2 years ago

8 0

Answer:

b: 5ft

Step-by-step explanation:

adoni [48]2 years ago

6 0

Answer:

your answer would be B (5)

Step-by-step explanation:

Just divide 15/3 will give you 5 ft.

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Jim and Sean went to the diner and bought two egg scrambles. Jim also got a cup of coffee for a dollar. If their total bill was

Alex73 [517]

Answer:

If only Jim purchased a cup of coffee, we will subtract its cost from the total;

9.50 - 1.00 = 8.50

Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.

Since they both bought eggs, then 2x = 8.50

x = $4.25, the price for each egg scramble

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2 years ago

6,10,14 ... Find the 30th term.

andriy [413]

Answer:

Step-by-step explanation:

$a_n=a_1+d(n-1)\\\\\\10-6=4 \ \ and\ \ 14-10=4\quad\implies\qquad d=4\\\\a_1=6\\\\\\a_{30}=6+4(30-1)=122$

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2 years ago

Which equation matches the graph of the absolute value function seen here?

nignag [31]

use a calculator instead of asking

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2 years ago

What percent of 80 is 8

murzikaleks [220]

Answer:

P = 10%

Step-by-step explanation:

Of means multiply and is means equals

P * 80 = 8

Divide each side by 80

P = 8/80

P = .1

Change to percent form

P = 10%

7 0

2 years ago

Read 2 more answers

Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives

Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

$F(x>t)=e^{-\lambda t}$

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

$F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535$

b) The probability of having to wait between 10 and 20 minutes

$F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10$

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

$F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286$

5 0

2 years ago