Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
The dimensions of the prism are 3 m by 4 m by 5 m.
Area = 2(3 * 4 + 3 * 5 + 4 * 5) = 2(12 + 15 + 20) = 2(47) = 94 m^2
Answer:find the operation first or try to estima your awnser
Step-by-step explanation:
Answer:
Number graph
Step-by-step explanation:
This way you can accurately count the number of each girl and boy
-3 + (-4)= -7
-3 times -4=12
negative plus a negative is still a negative. negative times a negative is a positive.
