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2 years ago

What is the equation for a geometric sequence with a first term of 4 and a second term of −8?

Mathematics

1 answer:

mihalych1998 [28]2 years ago

5 0

<h3>Answer:</h3>

$a_n=4(-2)^{n-1}$

<h3>Step-by-step explanation:</h3>

The common ratio is -8/4 = -2. The general formula for the n-th term is ...

... an = a1·r^(n-1) . . . . . . note the use of the caret (^) and parentheses

For r = -2 and a1 = 4, this becomes ...

... an = 4·(-2)^(n-1) . . . . approximately matches the 2nd selection

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Solve using the Pythagorean identity<br>

Lynna [10]

<h3> $\bold{Sin\theta_{1}=-\frac{4}{5}}$ </h3>

Answer:

Solution given

Cos $\displaystyle \theta_{1}=\frac{3}{5}$

consider Pythagorean theorem

$\bold{Sin²\theta+Cos²\theta=1}$

Subtracting $Cos²\theta$ both side

$\displaystyle Sin²\theta=1-Cos²\theta$

doing square root on both side we get

$Sin\theta=\sqrt{1-Cos²\theta}$

Similarly

$Sin\theta_{1}=\sqrt{1-Cos²\theta_{1}}$

Substituting value of $Cos\theta_{1}$

we get

$Sin\theta_{1}=\sqrt{1-(\frac{3}{5})²}$

<h3>Solving numerical</h3>

$Sin\theta_{1}=\sqrt{1-(\frac{9}{25})}$

$Sin\theta_{1}=\sqrt{\frac{16}{225}}$

$Sin\theta_{1}=\frac{\sqrt{2*2*2*2}}{\sqrt{5*5}}$

$Sin\theta_{1}=\frac{4}{5}$

Since

In IVquadrant sin angle is negative

$\bold{Sin\theta_{1}=-\frac{4}{5}}$

7 0

2 years ago

Read 2 more answers

YOU YES YOU WILL BE MARKED AS BRAINLIST TO YHIS QUESTION!!✔

bogdanovich [222]

Answer:

Step-by-step explanation:

Most of the numbers in the set are rational where there is only ONE nature number which is 16 and it's the greatest. Comes after is 15/20 which equals .75 and it's obviously larger than 0.65 which will come after. The negative number is the smallest so it goes last :)

5 0

2 years ago

How can you determine the number of solutions for an equation

ryzh [129]

The way to determine the number of solutions is to complete the problem in multiple different ways.

5 0

3 years ago

Apr 24,8:28:53 AM<br> Find the 98th term of the arithmetic sequence -10,-8, -6, ...

Nata [24]

Answer: 184

Step-by-step explanation:

The nth term of am arithmetic sequence is calculated as:

Nth term= a+(n-1)d

where a = first term

d = common difference

a = -10

d = -8 -(-10) = -8+10 = 2

98th term= a+(n-1)d

= -10 + (98-1)(2)

= -10 + (97×2)

= -10 + 194

= 184

The 98th term of the arithmetic sequence is 184

6 0

3 years ago

How do you find the perimeter and area of this shape?

mixas84 [53]

P = 12 + 6 + 8,5 = 18 + 8,5 = 26,5 mm

A = 12 × 4 / 2 = 48 / 2 = 24 mm²

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2 years ago