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3 years ago

12

Identify the maximum and minimum values of the function y = 3 cos x in the interval [–2π, 2π]. Use your understanding of transfo

rmations, not your graphing calculator.

1 answer:

8_murik_8 [283]3 years ago

5 0

You would need to do this with a graphing calculator

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Circle P has a radius of 14 feet. Circle Q has a diameter of 14 feet. What is the ratio of the circumference of P to the circumf

Salsk061 [2.6K]

Answer:

2:1

Step-by-step explanation:

Circle P has radius 14 feet.

The circumference of this circle is given by:

$C=2 \pi \: r$

We plug in the radius to get:

$C=2\pi \: \times 14 = 28\pi$

Circle Q has diameter 14 feet.

The circumference of this circle is given by

$C=\pi \: d$

We substitute the diameter d=14 to get,

$C=\pi \: \times 14$

$C=14\pi$

The ratio of the circumference of P to the circumference of Q is

$28 \pi: 14\pi = 2:1$

4 0

3 years ago

What is the slope of the line represented by 5x + 2y = -15.

olasank [31]

Answer:

5x + 2y = -15

2y = -15-5x

y = -5/2x-15/2

SLOPE: -5/2

3 0

3 years ago

Help me with number three please

Alexxandr [17]

Y2-Y1/X2-X1 = 7-22/1-4 = -15/-3 = 5
y=5x+ 0

3 0

3 years ago

Read 2 more answers

Like for like ? follow for follow ?

VikaD [51]

Answer:

fkdixisidskkxjx

Step-by-step explanation:

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6 0

2 years ago

Gavin has $7,500 to invest. He is considering two investment options. Option A pays 4% simple interest. Option B pays 3.15% inte

Leviafan [203]

Solution:

Principal =P= $ 7,500

Option A→(Simple interest)

Rate of interest= R=4%

Time( $T_{1}$ )=4 years

Time( $T_{2}$ )=6 years

Amount= Principal + Interest(Simple or compound interest)

Formula for Simple interest

$S.I=\frac{P\times R\times T}{100}$

$S.I_{1}=\frac{7500 *4*4}{100}=1200\\\\ S.I_{2}=\frac{7500 *4*6}{100}=1800$

Total amount after 4 years when interest is simple= 7500 +1200= $ 8700

Total amount after 6 years when interest is simple= 7500 +1800= $ 9300

Option B

Formula for amount(A) when interest is 3.15% compounded annually.

$A=P*(1+\frac{R}{100})^t$

$A_{4}=7500*(1+\frac{3.15}{100})^4\\\\ A_{4}=7500*(\frac{103.15}{100})^4\\\\ A_{4}=7500*(1.0315)^4\\\\ A_{4}=7500*1.1320\\\\ A_{4}=8490.60$

$A_{6}=7500*(1+\frac{3.15}{100})^6\\\\ A_{6}=7500*(\frac{103.15}{100})^6\\\\ A_{6}=7500*(1.0315)^6\\\\ A_{6}=7500*1.2045\\\\ A_{6}=9033.9286$

Total amount after 4 years when interest is compounded annually=$ 8491 (approx)

Total amount after 6 years when interest is compounded annually=$ 9034(approx)

4 0

3 years ago

Read 2 more answers