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3 years ago

Write the difference between Error and Uncertainty in 4 Easy Points..

Physics

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

Error is the difference between the true value of the measured value.... Uncertainty characterizes the range of value within which the true value is asserted to lie with some level of confidence

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A sanding disk with rotational inertia 3.8 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit

Elis [28]

Answer:

(a) Angular momentum of disk is $1.343\, \frac{kg.m^{2}}{s}$

(b) Angular velocity of the disk is $353\frac{rad}{s}$

Explanation:

Given

Rotational inertia of the disk , $I=3.8\times 10^{-3}kg.m^{2}$

Torque delivered by the motor , $\tau =17N.m$

Torque is applied for duration , $\Delta t=79ms=0.079s$

(a)

Magnitude of angular momentum of the disk = Angular impulse produced by the torque

$\therefore L=\tau \Delta t=17\times 0.079\frac{kg.m^{2}}{s}$

=> $L=1.343\, \frac{kg.m^{2}}{s}$

Thus angular momentum of disk is $1.343\, \frac{kg.m^{2}}{s}$

(b)

Since Angular momentum , $L=I\omega$

where $\omega$ = Angular velocity of the disk

$=>\omega =\frac{L}{I}=\frac{1.343}{3.8\times 10^{-3}}\frac{rad}{s}$

$\therefore \omega =353\frac{rad}{s}$

Thus angular velocity of the disk is $353\frac{rad}{s}$

5 0

4 years ago

What is measurement ?

bazaltina [42]

Answer:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

7 0

3 years ago

Read 2 more answers

Many physical properties, such as force and mass, cannot be measured directly. Rather, some other physical property is measured

Salsk061 [2.6K]

Answer:

u =0.269

Explanation:

To find the coefficient of friction we know the following formula

$F_{f} = uN$

Where

$F_{f}$ = Force of Friction

$u$ = Coefficient of Friction

$N$ = Normal Force

Thus we first find the Normal force (N). Remember that the Normal force is perpendicular to the surface, and is equal to the opposing component of Weight (W). Since the surface here is horizontal, then the Normal force will be equal to the Weight.

$N = mg\\ N = (2.12)(9.8)\\ N = 20.776 N$

Now we find the Force on the spring that caused the extension of 3.25cm or 0.0325m

$F_{f} = ke$

Where

$F_{f}$ = Force of Friction

$k$ = Force Constant

= extension

Hence

$F_{f} = ke\\ F_{f} = (172)(0.0325)\\ F_{f} =5.59N$

Now to find the coefficient of friction we use the first formula

$F_{f} = uN\\ 5.59 = u(20.776)\\ u =0.269$

4 0

3 years ago

White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the width of the first-order rainbow on a scr

Tema [17]

Answer:

Δy=0.431m

Explanation:

Diffraction grating with split space d,to find the fringe position ym,we must to find the angle from

dSinα=mλ

A grating with N slits or lines per mm has slit spacing of

d=1/N

d=(1/600mm)

d=1.67×10⁻³mm

For 400nm wavelength:

α=Sin⁻¹(mλ/d)

$\alpha =Sin^{-1}(\frac{400*10^{-9} }{1.67*10^{-6}} )\\ \alpha =13.910^{o}$

And the position of first order lowest wavelength fringe on the screen is:

$y_{1}=Ltan\alpha_{1}\\y_{1}=2tan(13.910)\\ y_{1}=0.49445m$

For 700nm wavelength:

α=Sin⁻¹(mλ/d)

$\alpha =Sin^{-1}(\frac{700*10^{-9} }{1.67*10^{-6}} )\\ \alpha_{2} =24.83^{o}$

And the position of first order highest wavelength fringe on the screen is:

$y_{2}=Ltan\alpha_{2}\\y_{2}=2tan(24.83)\\ y_{2}=0.925595m$

The difference between the first order lowest and highest wavelength fringe is

Δy=(0.925595 - 0.49445)m

Δy=0.431m

6 0

4 years ago

A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take

Juli2301 [7.4K]

To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

$T =2\pi \sqrt{\frac{L}{g}}$

Here,

L = Length

g = Acceleration due to gravity

We can realize that $2 \pi$ is a constant so it is proportional to the square root of its length over its gravity,

$T \propto \sqrt{\frac{L}{g}}$

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

$g \rightarrow 0 \Rightarrow T \rightarrow \infty$

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0

3 years ago