Answer:4A
Explanation:
Given
Mass is displace x= A units from its mean position x=0'
When it is set to free it will oscillate about its mean position with maximum amplitude A i.e. from x=-A to x=A
One cycle is completed when block returns to its original position
so first block will go equilibrium position x=0 and then to x=-A
from x=-A it again moves back to x=0 and finally back to its starting position x=A
so it travels a distance of A+A+A+A=4A
Their combined momentum after they meet is 0 .
The kinetic energy K = 0.5 * m * v² must be equal to the potential energy U = m * g * h.
m mass
v velocity
h height
g = 9.81m/s²
The mass m cancels out:
0.5 * v² = g * h
Solve for height h and transform to distance traveled.
(sin (4°) = height / distance)
Answer:
0.41
Explanation:
given,
mass of the car, m = 2290 Kg
initial speed = 10.5 m/s
mass of another car, M = 2780 Kg
distance moved = 2.80 m
coefficient of friction = ?
conservation of energy
m u = (M + m) V
2290 x 10.5 = (2290 + 2780) V
V = 4.74 m/s
using equation of motion
v² = u² + 2 a s
4.74² = 2 x a x 2.8
a = 4.02 m/s²
now using equation
a = μ g
4.02 = μ x 9.8
μ = 0.41
Answer: D.) 39,200 J
Via the equation of potential energy PE = mgh where m is mass, g is the average gravity on earth and h is the height. In this case m = 400 kg, g = 9.8, h = 10 m thus:

P.E.= 39,200 Joules