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Ratling [72]
3 years ago
6

What type of tectonic plate boundary exists along the edge of the North American plate near the coast of Northern California, Or

egon, and Washington?
A reverse fault, like the Cascadia subduction zone off the coast of Oregon and Northern California (north of Mendocino California), has relatively deep earthquakes—like the 1964 Alaska earthquake and the 2004 Sumatra earthquake that caused the Boxing Day Tsunami.
True
False
Megathrust earthquakes can be strongest in magnitude—stronger than a San Andreas earthquake like 1906
Physics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

-transform plate boundary

- false

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A small object is attached to the end of a relaxed, horizontal spring whose opposite end is fixed. The spring rests on a frictio
eduard

Answer:4A

Explanation:

Given

Mass is displace x= A units from its mean position x=0'

When it is set to free it will oscillate about its mean position with maximum amplitude A i.e. from x=-A to x=A

One cycle is completed when block returns to its original position

so first block will go equilibrium position x=0 and then to x=-A

from x=-A it again moves back to x=0 and finally back to its starting position x=A

so it travels a distance of A+A+A+A=4A    

7 0
3 years ago
Two billiard balls having the same mass and speed roll directly toward each other. What is their combined momentum after they me
stealth61 [152]
Their combined momentum after they meet is 0 .
3 0
3 years ago
A woman on a bicycle traveling at 10 m/s on a horizontal road stops pedaling as she starts up a hill inclined at 4.0º to the hor
IrinaK [193]
The kinetic energy K = 0.5 * m * v² must be equal to the potential energy U = m * g * h.

m mass
v velocity
h height
g = 9.81m/s²

The mass m cancels out:
0.5 * v² = g * h
Solve for height h and transform to distance traveled.
(sin (4°) = height / distance)

6 0
3 years ago
A 2290 kg car traveling at 10.5 m/s collides with a 2780 kg car that is initially at rest at the stoplight. The cars stick toget
avanturin [10]

Answer:

0.41

Explanation:

given,

mass of the car, m = 2290 Kg

initial speed = 10.5 m/s

mass of another car, M = 2780 Kg

distance moved = 2.80 m

coefficient of friction = ?

conservation of energy

m u = (M + m) V

2290 x 10.5 = (2290 + 2780) V

V = 4.74 m/s

using equation of motion

v² = u² + 2 a s

4.74² = 2 x a x 2.8

a = 4.02 m/s²

now using equation

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4.02 = μ x 9.8

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7 0
3 years ago
A 400.0 kg storage box is held 10 m above ground by a forklift. What is its gravitational potential energy? (PE = mgh)
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Answer: D.) 39,200 J

Via the equation of potential energy PE = mgh where m is mass, g is the average gravity on earth and h is the height.  In this case m = 400 kg, g = 9.8, h = 10 m thus:

P.E.=(400kg)(9.8\frac{m}{s^2} )(10m)=39,200 J

P.E.= 39,200 Joules

7 0
3 years ago
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