Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
F^1(x)=2x-16 To find the interverse interchange the variable and solve for y
Answer:
Step-by-step explanation:
Converte 80% into a decimal (devide it by 100) = 0.8
Then multiply 0.8 by 1.60 = 1.28 (final result)
Oscar played games vs number of points he scored is, C) positive, linear association.
Step-by-step explanation:
- no association is when points Oscar graph will remain between 8to10.
- number of games he scored his points remain the same which is mean.
- non linear is only when there is no straight line passing.
- Linear is either exponential or polynomial.
- Positive as the game increase he scoring abilities increases.
- Negative as the game increases his scoring decreases.
- Negative x axis will have more number of points.
- Negative y axis will high to low of the graph.
- Linear lines are best way to predict a data doesn't work will all data.
