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3 years ago

Carissa counts by 5s from 32 to 62. Which number does carissa count?

Mathematics

1 answer:

Anna35 [415]3 years ago

4 0

Answer:

32, 37, 42, 47, 52, 57, 62.

Step-by-step explanation:

It is given that Carissa counts by 5s from 32 to 62.

It means, we have to add 5 in the number to get the next number.

Add 5 in 32.

$32+5=37$

Now, add 5 in 37.

$37+5=42$

Similarly, continue the process.

$42+5=47$

$47+5=52$

$52+5=57$

$57+5=62$

Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.

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What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3

Gnoma [55]

Answer:

√30-√18+√55-√33/2

Step-by-step explanation:

What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3

Given the expression

√6+√11/√5+√3

Rationalize

√6+√11/√5+√3 × √5-√3/√5-√3

= √30-√18+√55-√33/√25-√9

= √30-√18+√55-√33 /5-3

= √30-√18+√55-√33/2

This gives the required quotient

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2 years ago

Find the surface area of the prism below. Please see the attachment and a. 108cm ^2 is incorrect. Thanks!

creativ13 [48]

Answer: OPTION B

Step-by-step explanation:

To solve this problem you must add the areas of each rectangle that form the prism;

The area of a rectangle can be calculated with the formula:

$SA=length*width$

There are three pairs of equal rectangles, then you can find the surface area of 3 rectangles and multiply each one by 2, then you obtain that the surface area of the prism is:

$SA_{prism}=2(6cm*2cm)+2(3cm*6cm)+2(3cm*2cm)=72cm^{2}$

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2 years ago

EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the

solong [7]

Answer:

<h2>a) f = sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f = sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v = (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

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2 years ago

You bought a new car in 2015 for $32,000 that is depreciating in value by 15% each year. Write a function to represent this situ

Hitman42 [59]

Function: x = years

x = $32,000-15%x

Value of car in 2020:

$8000

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2 years ago

Item 6 Graph △JKL and its image after a reflection in the y-axis. J(5, 3), K(1,−2), L(−3, 4)

posledela

Answer:

J(-5,3) K(-1,-2) L(3,4)

Step-by-step explanation:

Reflections over the y axis make the x its opposite. 5 would change to -5, 1 would change to -1, and -3 would change to 3.

7 0

2 years ago