The number of blueberry muffins that a baker makes each day is

Solve 2x^3+7x^2-2x-1=o

Mashcka [7]

Answer:

$x=\sqrt{3}-2\\x=-\sqrt{3}-2\\x=\frac{1}{2}$

Step-by-step explanation:

This is a hard one

We have to use the rational root theorem

$2x^3+7x^2-2x-1$ = 0

We have to find all the factors of a and d and put them in a fraction

$a=2\\d=-1\\\frac{1}{1,2}$

We then plug them into the equation to see if any of them work

The equation isn't true when plugging 1, but is true when plugging in 1/2

factored form of 1/2 is (2x-1)

Then we divide the original equation by (2x-1) (you can use synthetic division or long division, it would be hard to type out the process for that) to get $x^2+4x+1$

So now the equation is $(2x-1)(x^2+4x+1)$

Solve the second half of this equation using the quadratic formula to get

$\sqrt{3}-2$ and $-\sqrt{3}-2$

We already know the solution for the first half of the equation (1/2)

So the final answers are:

$x=\sqrt{3}-2, -\sqrt{3}-2, \frac{1}{2}$

8 0

3 years ago

Help me with this math problem please, only this part because I can't seem to solve the last one, I'd like an explanation but it

jonny [76]

Why....

________________

4 0

3 years ago

An education researcher claims that 58% of college students work year-round. In a random sample of 400 college students, 232

Hatshy [7]

Answer:

The proportion of college students who work year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58% of college students work year-round.

A random sample of 400 college students, 232 say they work year-round.

To test the researcher's claim use a one-proportion z-test.

The hypothesis can be defined as follows:

H₀: The proportion of college students who work year-round is 58%, i.e. p = 0.58.

Hₐ: The proportion of college students who work year-round is 58%, i.e. p ≠ 0.58. C

Compute the sample proportion as follows:

$\hat p=\frac{232}{400}=0.58$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0$

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

$p-value=2\times P(z$

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work year-round is 58%.

6 0

3 years ago

HELP ASAP. GIVING 20P AND BRAINLIEST

PilotLPTM [1.2K]

Answer:

B

Step-by-step explanation:

edge 2020

3 0

2 years ago

Read 2 more answers

What's the opposite reciprocal of -2

Ierofanga [76]

t h e r e c i p r i c l e o f - 2 i s 2

7 0

3 years ago