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DENIUS [597]
3 years ago
15

Can you help me solve the polynomial function? (college algebra) y=x^3+10x^2+3x-126

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

y = (x + 7) (x + 6) (x − 3)

Step-by-step explanation:

Using rational root theorem, possible rational roots are:

±1, ±2, ±3, ±6, ±7, ±9, ±14, ±18, ±21, ±42, ±63, ±126

Using trial and error, we find that +3 is one of the roots.

There are 3 ways to continue from here: continue using trial and error to look for other rational roots; use long division to factor; or use grouping.

Using grouping:

y = x³ + 10x² + 3x − 126

y = x³ + 10x² − 39x + 42x − 126

y = x (x² + 10x − 39) + 42 (x − 3)

y = x (x + 13) (x − 3) + 42 (x − 3)

y = (x (x + 13) + 42) (x − 3)

y = (x² + 13x + 42) (x − 3)

y = (x + 7) (x + 6) (x − 3)

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Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

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Help would be much appreciated :)
makkiz [27]

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Step-by-step explanation:

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