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e-lub [12.9K]
3 years ago
6

What is the value of y in the parallelogram below?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0
The sum of the adjacent angles of a parallelogram is always equal to 180°.

So we know that 3y + 108 = 180.

When we simplify that expression: 3y = 72
Isolate the y by divide both sides by 3: y = 24
Viefleur [7K]3 years ago
4 0

Answer: if you dont have 24 as an answer then choose 23, i got it right on Apex.

Step-by-step explanation:

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A function f is given by the data in the table. I am currently working with Derivatives but i can’t solve this one.
mariarad [96]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

One way to approximate the derivative at a point is by finding the slope of the secant line between points on either side. That is what is done in the attached spreadsheet.

  f'(0.1) ≈ (f(0.2) -f(0.0))/(0.2 -0.0) = -5 . . . for example

__

Another way to approximate the derivative is to write a polynomial function that goes through the points (all, or some subset around the point of interest), and use the derivative of that polynomial function.

These points are reasonably approximated by a cubic polynomial. The derivative of that polynomial at the points of interest is given in the table in the second attachment. (f1 is a rounding of the derivative function f')

6 0
3 years ago
I need Help please.....
Ira Lisetskai [31]

Answer:

what's up

Step-by-step explanation:

6 0
3 years ago
Subtract h - 1 from<br> h+4.<br> Oh+5<br> o h+5<br> 1h<br> 4<br> h+3
Soloha48 [4]

Answer:

Step-by-step explanation:

(h + 4) - (h-1) = h + 4 + h*(-1) - 1*(-1)

                    = h + 4 - h + 1

                   = h - h + 4 + 1

                    = 0h + 5

8 0
3 years ago
How do you do this question?
lukranit [14]

Answer:

0.001591

Step-by-step explanation:

The power series for arctan(x) is:

arctan(x) = ∑ (-1)ⁿ x²ⁿ⁺¹ / (2n + 1)

Substituting 5x:

arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺¹ / (2n + 1)

Multiply both sides by x:

x arctan(5x) = ∑ (-1)ⁿ x (5x)²ⁿ⁺¹ / (2n + 1)

Simplify:

x arctan(5x) = ∑ (-1)ⁿ (5x) (5x)²ⁿ⁺¹ / (10n + 5)

x arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺² / (10n + 5)

Multiply top and bottom by 5:

x arctan(5x) = ∑ (-1)ⁿ 5 (5x)²ⁿ⁺² / (50n + 25)

Integrate:

∫ x arctan(5x) = ∑ (-1)ⁿ (5x)²ⁿ⁺³ / ((50n + 25) (2n + 3))

Evaluate between x = 0.1 and x = 0:

∫₀⁰¹ x arctan(5x) = [∑ (-1)ⁿ (5x)²ⁿ⁺³ / ((50n + 25) (2n + 3))] |₀⁰¹

∫₀⁰¹ x arctan(5x) = ∑ (-1)ⁿ (0.5)²ⁿ⁺³ / ((50n + 25) (2n + 3))

This is an alternating series.  We can approximate it with Alternating Series Estimation.

bₙ₊₁ ≥ ε

(0.5)²⁽ⁿ⁺¹⁾⁺³ / ((50(n+1) + 25) (2(n+1) + 3)) ≥ 0.000001

(0.5)²ⁿ⁺⁵ / ((50n + 75) (2n + 5)) ≥ 0.000001

n ≥ 3

So the approximation is the sum of the terms from n=0 to n=3.

(-1)⁰ (0.5)²⁽⁰⁾⁺³ / ((50(0) + 25) (2(0) + 3))

+ (-1)¹ (0.5)²⁽¹⁾⁺³ / ((50(1) + 25) (2(1) + 3))

+ (-1)² (0.5)²⁽²⁾⁺³ / ((50(2) + 25) (2(2) + 3))

+ (-1)³ (0.5)²⁽³⁾⁺³ / ((50(3) + 25) (2(3) + 3))

= 0.0016667 − 0.0000833 + 0.0000089 − 0.0000012

= 0.001591

7 0
3 years ago
Ben decides to start a business walking dogs and cleaning swimming pools. It
3241004551 [841]

Answer:

It would be B (15x + 20x)

8 0
3 years ago
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