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grigory [225]
3 years ago
10

What is the perimiter of ABC with vertices A (-2,9), B(7-3), and c(-2,-3) in the coordinate plane?

Mathematics
1 answer:
Serggg [28]3 years ago
6 0

Answer:

|AB| = √((7 - (-2))^2 + (-3 - 9)^2) = 15

|BC| = √((-2 - 7)^2 + (-3 - (-3))^2) = 9

|AC| = √((-2 - (-2))^2 + (-3 - 9)^2) = 12

Perimeter = 15 + 9 + 12 = 36

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Ani was told to write the number four and eight hundredths. She wrote
JulsSmile [24]

Answer:

It would be 4.08, so Ani is wrong writing it as 4.8.

Step-by-step explanation:

So, with this, the number 4 is 4, a single-digit number. Anything below that has a decimal point before it. With the knowledge of there being 8 hundredths, first see this diagram explaining the terms for numbers after the decimal point:

0.1 --> 1 Tenth

0.01 --> 1 Hundredth

0.001 ---> 1 Thousandth

With this, we can see that it will be something of the likes of 4.01-4.09. Since there are 8 Hundredths, it would be 4.08, as 0.01 * 8 = 0.08.

Therefore, she is wrong because she wrote it as 4 and 8 tenths rather than 4 and 8 hundredths.

6 0
2 years ago
Daniela bought 132 unicorn toys from the store. She then bought 231 minion toys. About how many toys does she have altogether? (
ASHA 777 [7]

Answer:

The answer would be 363 but if u would round that answer to nearest hundred then it’s 400

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Find an​ nth-degree polynomial function with real coefficients satisfying the given conditions.
lesya692 [45]

Answer:

\displaystyle f(x) = -2(x-2)(x^2+4)

Step-by-step explanation:

We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.

First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.

Hence, we will have the three factors:

\displaystyle f(x) = a(x-(2))(x-(2i))(x-(-2i))

Where <em>a</em> is the leading coefficient.

Expand and simplify the second and third factors:

\displaystyle \begin{aligned} (x-(2i))(x-(-2i)) &= (x-2i)(x+2i) \\ \\ &= x(x-2i)+2i(x-2i) \\ \\ &= (x^2 - 2ix) + (2ix - 4i^2) \\ \\ &=x^2 + 4\end{aligned}

Hence:

\displaystyle f(x) = a(x-2)(x^2+4)

Since f(-1) = 30:

\displaystyle \begin{aligned}  f(x) &= a(x-2)(x^2+4) \\ \\ (30) &= a((-1)-2)((-1)^2+4) \\ \\ 30 &= -15a \\ \\ a&= -2\end{aligned}

In conclusion, third degree polynomial function is:

\displaystyle f(x) = -2(x-2)(x^2+4)

5 0
3 years ago
Given the function f(x)=3+1/8x find a formula for the inverse function
Goshia [24]
F-1(x) = 8x - 24

You can get this by switching the x and f(x) and then solving for f(x) 

f(x) = 3 + 1/8x ---> now switch them
x = 3 + 1/8f(x) ---> now subtract 3 from both sides
x - 3 = 1/8f(x) ---> now multiply both sides by 8
8x - 24 = f(x) ----> ANSWER
5 0
2 years ago
Solve system by elimination <br> -2x+2y =2<br> 4x-4y=4
serious [3.7K]

Answer:

there is no solution for the question

4 0
3 years ago
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