What is the perimiter of ABC with vertices A (-2,9), B(7-3), and c(-2,-3) in the coordinate plane?

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

Answer:

|AB| = √((7 - (-2))^2 + (-3 - 9)^2) = 15

|BC| = √((-2 - 7)^2 + (-3 - (-3))^2) = 9

|AC| = √((-2 - (-2))^2 + (-3 - 9)^2) = 12

Perimeter = 15 + 9 + 12 = 36

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