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miskamm [114]
3 years ago
7

Cuales son las raíces solución de la ecuación x^2-5x+4=0

Mathematics
1 answer:
Pepsi [2]3 years ago
7 0
2x - 5x + 4 = 0
- 3x = - 4
x = 4/3
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[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
Easy Points! Explain Well!
ddd [48]

Answer:

I am guessing it is 67 as for maybe the whole thing is 180 degrees. So 180 subtracted by 67 and 46 equals 67!!!

5 0
3 years ago
Read 2 more answers
2x + 5y = 10<br>5y<br>x +<br>2.<br>+<br>= 4​
elena-s [515]
Could you attach photo of a problem. It appears 2+..... =4 is missing
4 0
2 years ago
Find the ranges of these numbers 35 45 30 45 70
serg [7]

Answer:

The range is 40.

Step-by-step explanation:

Range is just the largest number minus the smallest.

70 - 30 = 40

5 0
3 years ago
What’s the answer to this?
Elina [12.6K]

Step-by-step explanation:

Line is passing through the points:

(-2,\:3)=(x_1,\:y_1) \:\&\: (2,\:5)=(x_2 ,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \frac{y -3}{ 3 -5} = \frac{x -(-2) }{-2 -2} \\ \\ \therefore \frac{y -3}{ - 2} = \frac{x -(-2) }{-4} \\ \\ \therefore \frac{y - 3}{1} = \frac{x +2}{2} \\ \\ \therefore \: y-3= \frac{x}{2} + \frac{2}{2} \\ \\\therefore \: y= \frac{x}{2} + 1 +3\\ \\ \huge \red{ \boxed{\therefore \: y= \frac{1}{2} \:x+ 4}}\\ is \: the \: required \: equation \: of \: line.

4 0
3 years ago
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