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3 years ago

How do I solve 10p+5=18p-6/2

Mathematics

1 answer:

mihalych1998 [28]3 years ago

3 0

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What does the linear inequality y ≥ −x − 3 look like?

kupik [55]

It is a line that divides the space into two.. The line is y=-x-3

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3 years ago

Carissa also has a sink that is shaped like a half sphere. The sink has a volume of 4000/ 3 * π in 3. One day, her sink clogged.

givi [52]

Answer:

Part a) 119 cups

Part b) 30 cups

Step-by-step explanation:

Part a)

step 1

Find the volume of the conical cup with a diameter of 4 in. and a height of 8 in

The volume of the cone (cup) is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4/2=2\ in$ ----> the radius is half the diameter

$h=8\ in$

assume

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(2^{2})8=33.49\ in^3$

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

$\frac{4,000}{33.49}= 119\ cups$

Part b)

step 1

Find the volume of the conical cup with a diameter of 8 in. and a height of 8 in

The volume of the cone (cup) is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=8/2=4\ in$ ----> the radius is half the diameter

$h=8\ in$

assume

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(4^{2})8=133.97\ in^3$

step 2

Find out how many cups of water must Carissa scoop out of the sink

Divide the volume of the sink by the volume of the cup

$\frac{4,000}{133.97}= 30\ cups$

7 0

3 years ago

Muffins cost $3.00 per dozen.

GenaCL600 [577]

Answer:

I agree with both of them

Step-by-step explanation:

A dozen is 12 muffins. Therefore, you pay $3.00 for 12 muffins.

We know that you pay $3.00 for 12 muffins we need to find out how much EACH muffin cost. For that we need to divide $3.00 by 12 which is 0.25.

Now we need to know how much it will cost us for 16 muffins. We use our equation 16*0.25 which is 4. Elena said she will pay 4 so she is right.

Andre said he will buy 8 muffins so we use our equation again 8*0.25 which is 2. He said he will pay 2 so he is right.

5 0

2 years ago

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr

Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at $27 mi/hr$ in for two hours. Therefore, the side $a$ is:

$a=(27 mi/hr)(2 hr)=54mi$

- The second ship travels at $18 mi/hr$ for $1.5 hours$ . Therefore, the side $b$ is:

$b=(18mi/hr)(1.5hr)=27mi$

- Now, you can calculate $c$ :

$c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi$

The answer is: $44 miles$

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2 years ago

What is the range of this graph

Arlecino [84]

Answer:

[0,12]

Step-by-step explanation:

7 0

3 years ago