135 feet is the length of the yard
I think the answer is 3/9 because there is 9 students running but only 3 of them win medals so I think it would be 3/9 or maybe something else
For this case we have that the equation that describes the height is:

Where,
v: initial speed
c: initial height
Substituting values we have:

Then, to find the time, we use the quadratic formula:

Substituting values we have:

Rewriting:



We discard the negative root because we want to find the time.
We have then:


Answer:
D. 
Answer:
x=12
Step-by-step explanation:
x=12