Solve the inequality. Show your work.
|4r + 8| ≥ 32
3 answers:
|4r + 8| ≥ 32
4r + 8 ≥ 32 or 4r + 8 ≤ -32 <em> inside of absolute value could be + or -</em>
4r ≥ 24 or 4r ≤ -40 <em>subtracted 8 from both sides</em>
r ≥ 6 or r ≤ -10 <em>divided both sides by 4</em>
Graph: ←---------------- -10 6 ------------------→
Interval Notation: (-∞, -10] U [6, ∞)
Okay here are the steps to solving this inequality:
First- <u><em>Break down the problem into these 2 equations</em></u>
4r + 8 ≥ 32 → - (4r + 8) ≥ 32
Second- <u>Solve the 1st equation: </u><u><em>4r + 8 ≥ 32</em></u>
r ≥ 6
Third- <u>Solve the 2nd equation: - (4r + 8) ≥ 32</u>
r ≤ -10
Lastly- <u>Collect all solutions </u>
<h2>
r ≥ 6 and r ≤ -10</h2>
Okay here are the steps to solving this inequality:
First- <u><em>Break down the problem into these 2 equations</em></u>
4r + 8 ≥ 32 → - (4r + 8) ≥ 32
Second- <u>Solve the 1st equation: </u><u><em>4r + 8 ≥ 32</em></u>
r ≥ 6
Third- <u>Solve the 2nd equation: - (4r + 8) ≥ 32</u>
r ≤ -10
Lastly- <u>Collect all solutions </u>
<h2>
r ≥ 6 and r ≤ -10</h2>
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