All categories

3 years ago

Stadiums maximum capacity is 66,655 people.if there are 61,364 people in the stadium what percent of it is unoccupied

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

6 0

100/66655*61364=92.0621108694%

You might be interested in

Q6. The diagram shows two similar solids, A and B.

solniwko [45]

Answer:

640cm³

Step-by-step explanation:

Length SF = ×2

Volume SF = ×2³ = ×8

Volume of B = 8 × 80 = 640cm³

6 0

3 years ago

-10.12 + 51 + 3 212 + 4 Select the true statement

Tatiana [17]

I think answer should be 20 please give me brainlest let me know if it’s correct or not okay thanks bye

6 0

3 years ago

Surri solved the equation x ^ 2 equals 49 and found that x equals 7 what error did Suro make

denpristay [2]

It does not look like Suro even made an error. She took the square root of both sides to get x = 7, I don't see any problem here.

7 0

3 years ago

Read 2 more answers

In Grafton, a rural area in Vermont, the distance (in meters) between telephone poles has a uniform distribution between 40 and

coldgirl [10]

Answer:

a) 60% probability that the distance is environment friendly.

b) The mean of the distances between the telephone poles is 52.5 meters.

c) The standard deviation of the distance between the telephone poles is 7.22 meters.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Uniform distribution between 40 and 65 meters.

This means that $a = 40, b = 65$

a) Any distance between poles greater than 50 meters is considered to be environment friendly. What is the probability that the distance is environment friendly?

This is $P(X > 50)$

We have that

$P(X \leq 50) + P(X > 50) = 1$

$P(X > 50) = 1 - P(X \leq 50)$

$P(X \leq 50) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X > 50) = 1 - P(X \leq 50) = 1 - 0.4 = 0.6$

60% probability that the distance is environment friendly.

b) Find the mean of the distances between the telephone poles

The mean of the uniform distribution is

$M = \frac{a + b}{2}$

$M = \frac{a + b}{2} = \frac{40 + 65}{2} = 52.5$

c) Find the standard deviation of the distance between the telephone poles.

The standard deviation of the uniform distribution is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

$S = \sqrt{\frac{(65-40)^{2}}{12}} = 7.22$

5 0

4 years ago

How can I solve that problem

drek231 [11]

What do we know so far:

$2\frac{2}{3}laps$ in $\frac{4}{15}hour$ ⇒ $\frac{8}{3}laps$ in $\frac{4}{15}hour$

*we converted the number of laps into improper fractions

$2\frac{2}{3} = \frac{8}{3}$

We want to know the number of laps in an hour

⇒ so we must find the rate which ⇒ lap/hour

$lap/hour =\frac{8/3laps}{4/15hours} =\frac{8}{3}*\frac{15}{4} =\frac{8}{4} *\frac{15}{3} =2*5=10laps/hour$

So William can run ⇒ 10 laps in one hour

Hope that helps!

8 0

2 years ago