Call the point where BK intersects AM point X. BX is the altitude of ∆ABM, and it is also the angle bisector of angle ∠ABM. Hence ∆ABM is isosceles, and AB ≅ MB.
M is the midpoint of BC, which is 12 inches long. Hence MB is half that length, or 6 inches.
Since AB is the same length as MB, which is 6 inches, ...
... AB is 6 inches.
The zeroes of the function will be
A quadratic function is given by ax² +bx+c = f(x)
The given quadratic function is
f(x) = 6x² +12x - 7
The zeroes of the function will be given by
f(0) = 0
6x² +12x - 7 = 0
The zeroes are given by
here
a = 6
b = 12
c = -7
Therefore the zeroes of the function will be
Therefore these are the two zeroes of the function.
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