Question

Plzzzzz help due tomorrow

Answer 1

Answer:

Q1 m² +10m+ 21

Q2

a) 3 (2 +3x)

b) (y+4) (y-4)

c) (2p-5) (p+2)

Step-by-step explanation:

Q1. expand and simplify (m+7)(m+3)

solution

(m+7)(m+3)

m² + 7m+ 3m + 21

m² +10m+ 21

Q2 Factorize  

a) 6 +9x

Answer  

Taking 3 common  

3 (2 +3x)

b) y² -16

answer  

y² -4                as formula a² –b² = (a+b)(a-b)

  (y+4) (y-4)

c) 2p² –p-10

So according to quadratic equation  

a=2  b=-1   c=-10         a x c =-20     b=-1

we need two number whose product is -20 and sum is -1

-5 x 4 = -20         -5 +4 = -1

2p² –p-10 = 2p² + 4p-5p-10

            =2p (p +2) -5 (p+2)

          = (2p-5) (p+2)

please mark me brainliest  :D