The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
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C =7
d is 6 times c+3
d=6c+3
d=6d+3 is equation
(if you sub, you would get 45 is weight)
C = 15x + 50
let c be $125 since c represents the cost
15x + 50 = 125
15x = 125 - 50
15x = $75
x = 75 ÷ 15
x = 5
Answer:

Step-by-step explanation:


Answer:

Step-by-step explanation:
The question is poorly formatted. The original question is:

We have:

Open bracket


Express 8 as 2^3



Express 2^3 as 8

Expand each exponent

Split



Factorize
