-3i+3/4+2i-9/3-3i=(3/4-9/3) +(-3i+2i-3i)=(3/4-3)+(-4i)=(3/4-12/4)-4i=
=-9/4-4i
The answer is a enlargement
Answer:
we conclude that the intervals in which the function P(t) is decreasing are:
Step-by-step explanation:
At x< 1, the function P(t) is decreasing
- A function p is an increasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x
- A function p is a decreasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>x
From the figure, it is clear that the function seems to be increasing
from (1, 3) and then 4 to onwards.
But it is clear that the function seems to be decreasing from the x < 1 and from the interval (3, 4).
Therefore, we conclude that the intervals in which the function P(t) is decreasing are:
This statement is false, there is no variable to make this statement true.
