Answer: whats the question
Step-by-step explanation:
Answer:
12 bouquets
Step-by-step explanation:
Let there be x number of roses and x number of tulips initially at the store. Each bouquet was made with 3 roses and 4 tulips. Assume that y bouquets were made in total.
If each bouquet was made with 3 roses and 4 tulips, then y bouquets will be made with 3y roses and 4y tulips.
After the bouquets were all made, there were 30 roses and 18 tulips left in the store. This means, if we subtract number of roses that were used in bouquets from total number of roses, the result must be 30. Likewise, for tulips the result would be 18. This can be represented as:
x - 3y = 30 Equation 1
x - 4y = 18 Equation 2
Subtracting Equation 2 from Equation 1, we get:
x - 3y - (x - 4y) = 30 - 18
x - 3y - x + 4y = 12
y = 12
Since y represents the number of bouquets made, we can conclude that 12 bouquets were made in the store.
Answer:
Step-by-step explanation:
<u>Exponential function:</u>
<u>Ordered pairs given:</u>
<u>Substitute x and y values to get below system:</u>
<u>Divide the second equation by the first one and solve for b:</u>
- 80/10 = b³
- b³ = 8
- b = ∛8
- b = 2
<u>Use the first equation and find the value of a:</u>
<u>The function is:</u>
A(x) = 3x + 1
b(x) = √(x-4)
Therefore
This composition of functions is only defined as a real number when x≥0.
Therefore its domain is x = [1,∞]
Answer: [1,∞]
Answer:
C. 128ft
Step-by-step explanation:
it's C because whenever it says and you're supposed to multiply always remember that :) = (which means area ofc) you're finding the so you multiply 16x8 and the you get your answer (: ignore the 640 you just focus on the 16 and 8 ok? 16x8=128! :))
<em /><em> </em><em /><em /><em /><em /><em /><em /><em /><em> </em><em /><em /><em /><em /><em> </em><em /><em /><em> </em><em /><em /><em /><em /><em /><em /><em> </em><em /><em /><em /><em /><em /><em> </em><em /><em /><em> </em><em /><em /><em> </em><em /><em /><em /><em> </em><em /><em /><em /><em> </em><em /><em /><em> </em><em /><em /><em /><em /><em /><em> </em><em /><em /><em /><em /><em> </em><em /><em /><em /><em /><em /><em /><em /><em> </em><em /><em /><em> </em><em /><em /><em /><em /><em /><em> </em><em /><em /><em /><em /><em /><em /><em /><em /><em /><em> </em><em> </em><em>></em><em>:</em><em>(</em>
