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Mademuasel [1]
3 years ago
14

A right triangle has side lengths of 3, 4, and x. Find x if it is the hypotenuse.

Mathematics
1 answer:
crimeas [40]3 years ago
4 0

Answer:

5

Step-by-step explanation:

3² + 4² = 25

√25 = 5

use the formula

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Find the value of x. Then tell whether the angles are complementary or supplementary.
Luba_88 [7]

Answer:

Hello! answer: x = 60

Step-by-step explanation:

This is a complementary angle so it will add up to 90 degrees! here is a demonstration picture for how I solved it! Hope that helps!

3 0
3 years ago
Read 2 more answers
A reflecting pool is shaped like a right triangle with one leg along the wall of a building. the hypotenuse is 9 feet longer tha
morpeh [17]

Answer:

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

Step-by-step explanation:

In the question, the shape of the pool is right triangle.

Let the leg side along the wall to be the x ft

Let the other leg side  to be 7+x ft

Let the longest side/hypotenuse to be x+9 ft

Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse

This means;

x^2 +(x+7)^2=(x+9)^2\\\\

Expand the terms in brackets

x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81

collect like terms

x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0

solve for x in the quadratic equation by factorization

x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8

Taking the positive value of x;

x=8ft

Finding the lengths

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

6 0
3 years ago
Hexagon ABCDEF → hexagon A'B'C'D'E'F'. How can the transformation shown be described? Check all that apply.
AveGali [126]
The correct answer would be c,and f 
5 0
3 years ago
Read 2 more answers
I cant figure this one out at all
eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

4 0
2 years ago
A father had $160.he gave his son a certain amount. the second son got $10 more and the last son got 3 time more than the first
Bumek [7]
10 x 3= 30 + 10 = 40

160
- 40
——-
120
4 0
3 years ago
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