Answer:
1a- Alternate Exterior Angles
1b- Alternate Interior Angles
1c-Alternate Exterior Angles
1d-Alternate Interior Angles
1e-Alternate Exterior Angles
1f-Alternate Interior Angles
2a-None
2b-None
2c-Alternate Exterior Angles
2d-None
2e-Alternate Interior Angles
2f-None
2g-None
2h-None
2i-None
2j-None
The answer will be 21u^6v^8
Answer:
C. The electric car is not moving at 0 seconds and 12 seconds.
Step-by-step explanation:
Given:
The table given is:
x 0 2 4 6 8 10 12
y 0 45 72 81 72 45 0
From the above table, we observe that the car starts from rest and its speed increases from 0 to 6 seconds, the maximum speed being 81 mph.
After 6 seconds, the speed of the car goes on decreasing till it stops at time equal to 12 seconds.
So, the speed of the car at the start when
is 0 mph as it is at rest at that time.
Also, when the time is
, the car has come to a stop and thus its speed has reduced to 0 mph again. So, the car is not moving after 12 seconds.
From the above conclusion, we can say that only option C is correct.
The electric car is not moving at 0 seconds and 12 seconds.
Answer:
Associative.
Step-by-step explanation:
In addition and multiplication, it does not matter which two numbers you put together first. On the left aide 6 is associated with 3. On the right side 3 is grouped with 7. It doesn't matter where 3 goes. You still get the same answer.
(6 + 3) + 7 = 6 + (3 + 7)
9 + 7 = 6 + 10
16 = 16
Recall your d = rt, distance = rate * time
so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.
now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".

so, 2hours and 36 minutes.