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2 years ago

Find the length of a segment drawn on a number line with its endpoints at 13 and -46

Mathematics

2 answers:

sashaice [31]2 years ago

7 0

Length = 59

From -46 to 0---------------46

From 0 to 13----------------13

Total ------------------------59 (46=13)

marin [14]2 years ago

7 0

Answer:

Step-by-step explanation:

Because you are finding distance on a number line, the answer will be positive (you can't be a negative amount away from something). You can add 13 to 46, each getting to 0. Your answer is 59.

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2 years ago

A bicyclist covered 5/7 of his route and an additional 40 miles. He has yet to cover 118 miles less than 0.75 of his route. How

Liula [17]

Answer:

168 miles.

Step-by-step explanation:

5/7x+40+0.75x−118=x

Step 1: Simplify both sides of the equation.

5/7x+40+0.75x−118=x

5/7x+40+0.75x+−118=x

(5/7x+0.75x)+(40+−118)=x(Combine Like Terms)

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1.464286x−78=x

Step 2: Subtract x from both sides.

1.464286x−78−x=x−x

0.464286x−78=0

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0.464286x−78+78=0+78

0.464286x=78

Step 4: Divide both sides by 0.464286.

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2 years ago

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zaharov [31]

Answer:

x = 13.4

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

x² + 6.8² = 14.1²

x² = 14.1² - 6.8²

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2 years ago

The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

$\\$

To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

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