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Norma-Jean [14]
3 years ago
10

State what additional information is required in order to know that the triangles are congruent by AAS. part 2

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Step-by-step explanation:

The trick is to find the third angle

180 - A - <BCA = <CBA

180 - X - <BCX = <CBX

Everything else is OK

<CBA = <CBX                  Equals equated to an equal express = an equal expression.

Now by a little slight of hand, you get the two triangles to be equal by ASA, which always works.

Cheating you say? There is no such thing as cheating if it correct and it works.

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Professor Harris is teaching a continuing education class at the local community college. He created the following box plot from
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Step-by-step explanation:

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3 years ago
What is the factor of x³ 5x² 2x 24?
Delvig [45]

The factors of the expression x³-5x²-2x+24 are: (x+2)(x-3)(x-4)

<h3>What is a factor?</h3>

A factor is a number that completely divides another number.

In other words, since the result may be divided by the two whole numbers we are multiplying, they are factors of the result if multiplying two whole numbers produces a result.

The numbers that can divide a number exactly are called factors.

There is none left over after division as a result.

The numbers you multiply together to produce another number are called factors.

A factor is hence the division of another number.

So, we have the expression: x³-5x²-2x+24

Now, calculate the factors as follows:

x³-5x²-2x+24

We already know that: P(-2) = 0

Hence, x+2 is a factor.

Now, other factors are: x² - 7x + 12

x² + 4x + 3x + 12

(x - 3)(x - 4)

Therefore, the factors of the expression x³-5x²-2x+24 are: (x+2)(x-3)(x-4)

Know more about the factors here:

brainly.com/question/24351176

#SPJ4

Correct question:
What is the factor of x³-5x²-2x+24?

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11 months ago
The Cost of producing n items is given as C = 5 + 2n, where 5 is initial cost and 2 is a cost per item. Profit is given as P = 3
aleksandrvk [35]
P=5 and initial to the 3 price
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Find the value of all trigonometric functions of 135°
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Answer:

sin (- 135°)= – sin 135°= – sin (1 × 90°+ 45°) = – cos 45° = – 1√2

cos (- 135°)= cos 135°= cos (1 × 90°+ 45°) = – sin 45°= – 1√2

tan (- 135°) = – tan 135° = – tan ( 1 × 90° + 45°) = – (- cot 45°) = 1

csc (- 135°)= – csc 135°= – csc (1 × 90°+ 45°)= – sec 45° = – √2

sec (- 135°)= sec 135°= sec (1 × 90°+ 45°)= – csc 45°= – √2

cot (- 135°) = – cot 135° = – cot ( 1 × 90° + 45°) = – (-tan 45°) = 1

Step-by-step explanation:

hope this helps

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